0.5x^2+5x-12=0

Solution for 0.5x^2+5x-12=0 equation:

0.5x^2+5x-12=0

a = 0.5; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·0.5·(-12)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-7}{2*0.5}=\frac{-12}{1}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+7}{2*0.5}=\frac{2}{1}
=2
$